Question

\(4\dfrac{1}{4}+\dfrac{2}{3}:x=5\dfrac{4}{9}\)

Answer 1

Giải:

\(4\dfrac{1}{4}+\dfrac{2}{3}:x=5\dfrac{4}{9}\)

\(\Leftrightarrow\dfrac{17}{4}+\dfrac{2}{3x}=\dfrac{49}{9}\)

\(\Leftrightarrow\dfrac{2}{3x}=\dfrac{43}{36}\)

\(\Leftrightarrow3x.43=36.2\)

\(\Leftrightarrow129x=72\)

\(\Leftrightarrow x=\dfrac{72}{129}=\dfrac{24}{43}\)

Vậy ...

Answer 2

\(4\dfrac{1}{4}\) + \(\dfrac{2}{3}\) : x = 5\(\dfrac{4}{9}\)

\(\dfrac{17}{4}\) + \(\dfrac{2}{3}\) : x = \(\dfrac{49}{9}\)

\(\dfrac{2}{3}\) : x = \(\dfrac{49}{9}\) - \(\dfrac{17}{4}\)

2/3 : x = 196/36-153/36

2/3 : x = 196-153/36

x = 43/36 x 2/3

x = 43/54

Answer 3

4\(\dfrac{1}{4}\)+\(\dfrac{2}{3}\):x= 5\(\dfrac{4}{9}\)

\(\dfrac{17}{4}\) + \(\dfrac{2}{3x}\) = \(\dfrac{49}{9}\)

\(\dfrac{2}{3x}\)= \(\dfrac{43}{36}\)

3x.43 = 36.2

129.x =72