Question

\(|x+\dfrac{1}{3}|-4=-1\)

Answer 1

\(\left|x+\dfrac{1}{3}\right|-4=-1\)

\(\left|x+\dfrac{1}{3}\right|=-1+4=3\)

\(x+\dfrac{1}{3}=\pm3\)

\(x=\left\{2\dfrac{2}{3};-3\dfrac{1}{3}\right\}\)

Answer 2

\(|x+\dfrac{1}{3}|-4=-1\)

\(\Rightarrow|x+\dfrac{1}{3}|=-1+4=3\)

\(\Rightarrow x+\dfrac{1}{3}=\pm3\)

*Với \(x+\dfrac{1}{3}=3\Rightarrow x=3-\dfrac{1}{3}=\dfrac{8}{3}=2\dfrac{2}{3}\)

*Với \(x+\dfrac{1}{3}=-3\Rightarrow x=-3-\dfrac{1}{3}=-3\dfrac{1}{3}\)

Answer 3

\(\left|X+\dfrac{1}{3}\right|-4=-1\)
\(\Rightarrow\left|x+\dfrac{1}{3}\right|=-1+4=3\)

\(\Rightarrow x+\dfrac{1}{3}=\pm3\)

với x+\(\dfrac{1}{3}=3\Rightarrow x=-3-\dfrac{1}{3}=-3\dfrac{1}{3}\)

với x+\(\dfrac{1}{3}=3\Rightarrow x=3-\dfrac{1}{3}=\dfrac{8}{3}=2\dfrac{2}{3}\)