Question

X/3=y/7;y/2=z/5 và x+y+z=-110

Giúp mình với

Answer 1

\(\dfrac{x}{3}=\dfrac{y}{7};\dfrac{y}{2}=\dfrac{z}{5}\Rightarrow\dfrac{x}{6}=\dfrac{y}{14}=\dfrac{z}{35}\)

Áp dung t/c dãy tỉ số = nhau, ta có :

\(\dfrac{x}{6}=\dfrac{y}{14}=\dfrac{z}{35}=\dfrac{x+y+z}{6+14+35}=\dfrac{-110}{55}=-2\)

\(\Rightarrow\dfrac{x}{6}=-2\Rightarrow x=-12\)

\(\dfrac{y}{14}=-2\Rightarrow y=-28\)

\(\dfrac{z}{35}=-2\Rightarrow z=-70\)

Answer 2

x = - 12

y = - 28

z = - 70