Question

(x+3)x(2y+1)=5

Answer 1

(x+3)(2y+1)=5

=>\(\left(x+3\right)\left(2y+1\right)=1\cdot5=5\cdot1=\left(-1\right)\cdot\left(-5\right)=\left(-5\right)\cdot\left(-1\right)\)

=>\(\left(x+3;2y+1\right)\in\left\{\left(1;5\right);\left(5;1\right);\left(-1;-5\right);\left(-5;-1\right)\right\}\)

=>\(\left(x;2y\right)\in\left\{\left(-2;4\right);\left(2;0\right);\left(-4;-6\right);\left(-8;-2\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(-1;2\right);\left(2;0\right);\left(-4;-3\right);\left(-8;-1\right)\right\}\)