\(x^3-4x^2+4-x=0\)
\(\Leftrightarrow x^2\left(x-4\right)-\left(x-4\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\x-1=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=1\\x=-1\end{matrix}\right.\)
-Vậy \(S=\left\{4;1;-1\right\}\)
a,x^2-9x+20=0
b,x^3-4x^2+5x=0
c,x^2=2x-15=0
d,(x^2-1)^2=4x+1
e,4x^3-9x^2+6x-1=0
f,x^4-4x^3-x^2+16x-12=0
10x+3/12=1+6:8x/9
2x+7x5 5x+1=0
2x(x-5)-x+5=0
(x+3)^2-(5-x)(x+3)=0
(x+2)(3-4x)=x^2+4x+4
a)x(x+3)(x-3) - (x+2)(x^2 -2x +4)=0
b)(x+2)(3-4x)=x^2+4x+4
c)x(2x-7)-4x+14=0
d)3x-15=2x(x-5)
giải phương trình giúp mình với ạ
a) (3x+2)(x^2-1)=(9x^2-4)(x+1)
b) (x+2)(3-4x)=x^2+4x+4
c) (2x-5)^2-(x+2)^2=0
d) (x^2-2x+1)-4=0
CÁC CAO NHÂN GIẢI GIÚP MÌNH VỚI
Giải các phương trình sau:
1) (3x 1)(7 4x) 0
2) 3x^2 + 6x = 0
3) (x 5)(x 1) (x 5)(4x 7) 0
4) x^2-4-(x-5)(2-x) = 0
5) X^3-1=x(x-1)
6) (2-x)(3x+3)(4x-1)=0
Bài 1 : Giải các phương trình sau:1) 5-(x-6)=4(3-2x) 2) (x-3)(x+4)-2(3x-2)=(x-4)2 3)3-x(1-3x)=5(1-2x) 4)9x-1=(3x+1)(4x+1) 5)2x(x-1)=x2-1 6)x2-5x2+6x=0 7)x2+4x-5=0 8)x3+9x2-4x-36=0
a, x^3+x^2-x-1=0
b, x^3+x^2-4x-4=0
c,x^3+x^2+4=0
d, (x-1)^2(x--3)+(x-1)^2(x+3)
e,x^4-5x^3+5x^2+5x-6=0
1,Giải PT sau
a, (5x+3)(x2+4)(x-4)=0
b, (4x-1)(x-3)-(x-2)(5x+2)=0
c, (x+3)(x-5)+(x+3)(3x-4)=0
d, (x+6)(3x-1)+x2-36=0
e, 0,75x(x+5)=(x+5)(3-1,25x)
a) (5x-15)(4+6x)=0
b) (2x-1)(5x-6)(1/2x-3/4)=0
c) (3-4x)(2x-3/4-x-4/3)=0
d) (2/3x-1/6)[5(x-1)-3/2-(2-3)(x-1)/3]=0
\(\left(x-\frac{3}{4}\right)^2+\left(x-\frac{3}{4}\right)\left(x-\frac{1}{2}\right)=0\)
\(\left(4x-\frac{4x-3}{5}-\frac{2\left(x+3\right)}{7}\right)=0\)
Giup minh voi cac ban oi
