Question

x\(^2\)+(y-\(\dfrac{1}{10}\))\(^4\)=0

Answer 1

Vì \(x^2\ge0\forall x\)

\(\left(y-\dfrac{1}{10}\right)^4\ge0\forall y\)

\(\Rightarrow x^2+\left(y-\dfrac{1}{10}\right)^4\ge0\forall x,y\)

Mà \(x^2+\left(y-\dfrac{1}{10}\right)^4=0\)

\(\Rightarrow\left\{{}\begin{matrix}x^2=0\\\left(y-\dfrac{1}{10}\right)^4=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=0\\y-\dfrac{1}{10}=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=0\\y=\dfrac{1}{10}\end{matrix}\right.\)

Vậy \(x=0;y=\dfrac{1}{10}\)