Ta có: \(\left(x+2\right)\left(x-2\right)+5x^2=\left(3x+1\right)^2-3x^2\)
\(\Leftrightarrow x^2-4+5x^2=9x^2+6x+1-3x^2\)
\(\Leftrightarrow6x^2-4=6x^2+6x+1\)
\(\Leftrightarrow6x^2-4-6x^2-6x-1=0\)
\(\Leftrightarrow-6x-5=0\)
\(\Leftrightarrow-6x=5\)
hay \(x=\frac{-5}{6}\)
Vậy: \(x=\frac{-5}{6}\)
GPT sau:
a) ( x-1)(5x+3)= (3x - 8 )(x-1)
b) 3x ( 25x + 15 )- 35 ( 5x+3) = 0
c) (2-3x ) ( x-11)=(3x-2)(2- 5x)
Giups mk vs thank cacs bn
1) (4x-10)(24+5x) =0
2) 0,5x(x-3)=(x-3)(2,5x-4)
3) 4x2-1=(2x+1)(3x-5)
4) (2-3x)(x+11)=(3x-2)(2-5x)
(x+2)(x−2)+5x^2=(3x+1)−3x^2
a)(x-1)(x^2+5x-2)-x^3+1=0
b)5(x^2+3x)-9(3x+3)=x^2-36
(3x+1)(3x-1)=(2x-1)^2 + 5x(x-2)
giải hộ mk vs
1/2x^4+3x^3-x^2+3x+2=0
2/x^4-5x^3+7x^2-5x-16=0
3/(x+2)^4+(x+4)^4=16
Giải phương trình sau:
1) (5x+1)2=(3x-2)2
2) 3x(25x+15)-35(5x+3)=0
3) (x-2)3=(2x+1)3
4) (x-1)(x2+5x-2)-x3+1=0
5) x2+(x+2)(11x-7)=4
giải các phương trình
a) (3x-2)(3x-1) = (3x+1)2
b) (4x-1)(x+1) = (2x-3)2
c) (5x+1)2 = (7x-3)(7x+2)
d) (4-3x)(4+3x)=(9x-3)(1-x)
e) x(x+1)(x+2)(x+3)=24
g) (7x - 2)2= (7x-3)(7x+2)
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
