ĐK \(x\ge-\dfrac{3}{2}\)
\(\Leftrightarrow x^2+4x+5-2\sqrt{2x+3}=0\)
\(\Leftrightarrow x^2+2x+1+2x+3-2\sqrt{2x+3}+1=0\)
\(\Leftrightarrow\left(x+1\right)^2+\left(\sqrt{2x+3}-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=0\\\sqrt{2x+3}-1=0\end{matrix}\right.\Rightarrow x=-1\)