\(\Leftrightarrow2x^2+x-2x-1+\left(x+1\right)^3=0\)
\(\Leftrightarrow x^3+3x^2+3x+1+2x^2-x-1=0\)
=>x^3+5x^2+2x=0
=>x(x^2+5x+2)=0
hay \(x\in\left\{0;\dfrac{-5+\sqrt{17}}{2};\dfrac{-5-\sqrt{17}}{2}\right\}\)
\(\Leftrightarrow2x^2+x-2x-1+\left(x+1\right)^3=0\)
\(\Leftrightarrow x^3+3x^2+3x+1+2x^2-x-1=0\)
=>x^3+5x^2+2x=0
=>x(x^2+5x+2)=0
hay \(x\in\left\{0;\dfrac{-5+\sqrt{17}}{2};\dfrac{-5-\sqrt{17}}{2}\right\}\)
Tìm x, biết:
\(\left(x^2+\dfrac{1}{2}x\right):\dfrac{1}{2}x-\left(2x+1\right)^3:\left(2x+1\right)^2+\left(x+1\right)^5:\left(x+1\right)^2=0\)
tìm x,biết:
a)(8x^2-4x):(-4x)-(x+2)=8
b)(2x^4-3x^3+x^2):(-1/2x^2)+4(x-1)^2=0
BT: Thực hiện tính
( 3xn-1 + 6x2n+2 ) : 2x1+n
BT: Tìm x
a, 3a3 ( x2 - 1)4 : 3a3 ( x2 - 1)3 = 15
b, x3(2x - 1)m+2 : x3 (2x -1)m-1 - 35 : 32 = 0
tìm x, biết :
a, 5x (x-1) -(1 -x) =0
b, (x - 3)2 - (x +3)2 = 24
c, 2x ( x2 -4) = 0
d, 2(x+5) - x2 - 5x = 0
e, (2x-3)2 - (x +5)2 = 0
f, 3x3 -48x =0
1. tìm x
a. (4x^4 + 3x^3) : (-x^3) + (15x^2 + 6x) : (3x) = 0
b. (x^2 - 1/2x) : 2x-(3x-1)^2 : (3x-1) = 0
2. tìm n thuộc N để phép chia là phép chia hết
a. (14x^5 - 7x^3 + 2x) : 7x^n
b. (25x^7y^6 - 10x^5y^4 - 6x^3y^2) : (-3x^ny^n)
1. Chia đa thức:
(x^3y^3 - 1/2xy^3 - x^3y^2) : 1/3x^3y^2
(x^3 + 8y^3) : (x + 2y)
[ 5(a - b)^3 + 2(a - b)^2 ] : (b - a)^2
(x^3 - 3x^2 + x - 3) : (x - 3)
(12x^2 - 14x + 3 - 6x^3 + x^4) : (1 - 4x + x^2)
(2x^2 - 5x^3 + 2x + 2x^4 - 1) : (x^2 - x - 1)
giúp mình nha các bạn! ^^
tìm x: \(x^3\left(2x-1\right)^{m+2}:x^3\left(2x-1\right)^{m-1}-3^5:3^2\)
tìm x biết : (x2 - 1/2x ) : 2x - ( 3x-1 )2 : ( 3x - 1 ) = 0
Giúp mình bài này nhé Tìm x a) ( 4x^4 + 3x^3 ) : ( - x^3 ) + ( 15 x^3 + 6x ) : 3x =0 b) ( x^2 - 1/2x ) : 2x - ( 3x - 1)^2 : ( 3x - 1) = 0 Cứu mình với