\(\left\{x^2-\left[6^2-\left(8^2-9\cdot7\right)^3-7\cdot5\right]^3-5\cdot3\right\}^3=1\\ \Rightarrow x^2-\left[36-\left(64-63\right)^3-35\right]^3-15=1\\ \Rightarrow x^2-\left[36-35-1^3\right]^3=16\\ \Rightarrow x^2-0^3=16\\ \Rightarrow x^2=16\\ \Rightarrow x=\pm4\)Vậy \(x=\pm4\)
{\(x\)2-[62-(82-9.7)3-7.5]3-5.3}3=1
{\(x\)2-[36-(64-63)3-35]3-15}3=1
{\(x\)2-[36-1-35]3-15}3=1
{\(x\)2-0-15}3=13
\(x\)2-0=1+15
\(x\)2-0=16
\(x\)2=16+0
\(x\)2=16
\(x\)2=16⇒42
\(x\)2=4
