\(|x+2|-4=6\)
\(\Rightarrow |x+2|=6+4\)
\(\Rightarrow |x+2|=10\)
\(\Rightarrow\left[ \begin{array}{l}x+2=10\\x+2=-10\end{array} \right. \)
\(\Rightarrow\left[ \begin{array}{l}x=8\\x=-12\end{array} \right. \)
- Vậy \(x \in \{8;-12\}\)
\(\left|x+2\right|-4=6\)
\(\Leftrightarrow\left|x+2\right|=10\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=10\\x+2=-10\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-12\end{matrix}\right.\)
à nhầm x=8 hoặc x=-12 nha
Mình tính nhầm
\(\left|x+2\right|-4=6\)
\(\left|x+2\right|=6+4\)
\(\left|x+2\right|=10\)
⇒\(\left[{}\begin{matrix}x+2=10\\x+2=-10\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=-12\end{matrix}\right.\)
vậy x∈{8,-12}
|x+2|-4=6
|x+2| =6+4
|x+2| =10
x =10-2
x =8
Vậy x=8
