6, \(x=\dfrac{9}{2}+\dfrac{1}{2}=\dfrac{10}{2}=5\)
7, \(x=-\dfrac{3}{4}-\dfrac{5}{4}=-\dfrac{8}{4}=-2\)
8, \(x=\dfrac{5}{7}-\dfrac{2}{7}=\dfrac{3}{7}\)
9, \(x=\dfrac{1}{3}+\dfrac{4}{3}=\dfrac{5}{3}\)
10, \(x=-\dfrac{7}{2}-\dfrac{5}{2}=-\dfrac{12}{2}=-6\)
\(6,x-\dfrac{1}{2}=\dfrac{9}{2}\Leftrightarrow x=5\)
\(7,x+\dfrac{5}{4}=\dfrac{-3}{4}\Leftrightarrow x=-2\)
\(8,x+\dfrac{2}{7}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{3}{7}\)
\(9,x-\dfrac{4}{3}=\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{3}\)
\(10,x+\dfrac{5}{2}=\dfrac{-7}{2}\Leftrightarrow x=-6\)
\(x-\dfrac{1}{2}=\dfrac{9}{2}\)
\(x\) \(=\dfrac{9}{2}+\dfrac{1}{2}=\dfrac{10}{2}=5\)
\(x+\dfrac{5}{4}=\dfrac{-3}{4}\)
\(x\) \(=\dfrac{-3}{4}+\dfrac{-5}{4}=\dfrac{-8}{4}=-2\)
\(x+\dfrac{2}{7}=\dfrac{5}{7}\)
\(x\) \(=\dfrac{5}{7}+\dfrac{-2}{7}=\dfrac{3}{7}\)
\(x-\dfrac{4}{3}=\dfrac{1}{3}\)
\(x\) \(=\dfrac{1}{3}+\dfrac{4}{3}=\dfrac{5}{3}\)
\(x+\dfrac{5}{2}=\dfrac{-7}{2}\)
\(x\) \(=\dfrac{-7}{2}+\dfrac{-5}{2}=\dfrac{-12}{2}=-6\)