Question

x² - 4 + *(x-2)²

Answer 1

Nhầm :v sửa lại :

$x^2-4+(x-2)^2$

$=x^2-2^2+(x-2)(x-2)$

$=(x-2)(x+2)+(x-2)(x-2)$

$=(x-2)(x+2+x-2)$

$=(x-2)2x$

Answer 2

Ta có : $x^2-4+(x-2)^2$

$=x^2-2^2+(x-2)^2$

$=(x-2)(x+2)+(x-2)^2$

$=(x-2)(x+2+1)$

$=(x-2)(x+3)$