Question

x²-3xy²-3x²y - y²

Answer 1

\(x^2-3xy^2-3x^2y-y^2\)

\(=\left(x^2-y^2\right)-\left(3xy^2+3x^2y\right)\)

\(=\left(x-y\right)\left(x+y\right)-3xy\left(y+x\right)\)

\(=\left(x-y\right)\left(x+y\right)-3xy\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-3xy\right)\)

Answer 2

x²-3xy²-3x²y - y²

=(x²-y²)-(3xy²+3x²y)

=(x-y)(x+y)-3xy(y+x)

=(x+y)(x-y-3xy)

Answer 3