Question

\(x^2-16x+60\)

Answer 1

= 0 nữa nha 

Answer 2

\(x^2-16x+60=0\)

\(\Leftrightarrow x^2-10x-6x+60=0\)

\(\Leftrightarrow x\left(x-10\right)-6\left(x-10\right)=0\)

\(\Leftrightarrow\left(x-6\right)\left(x-10\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-6=0\\x-10=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=6\\x=10\end{array}\right.\)

 

Answer 3

\(x^2-16x+60\)
\(=x^2-6x-10x+60\)
\(=x\left(x-6\right)-10\left(x-6\right)\)
\(=\left(x-6\right)\left(x-10\right)\)