\(x^2-10x=-25\\ \Leftrightarrow x^2-10x+25=0\\ \Leftrightarrow\left(x-5\right)^2=0\\ \Leftrightarrow x-5=0\\ \Leftrightarrow x=5\\ Vậy\text{ }x=5\)
\(x^2-10x+25=0\)
\(\left(x-5\right)^2=0\)
x=5
x2 - 10x = - 25
=> x2 - 10x + 25 = 0
=> ( x - 5 )2 = 0
=> x - 5 = 0
=> x = 5
Vậy x =5
x2-10x=-25
=>x2-10x+25=0
=>(x-5)2=0
=>x-5=0
=>x=5