Question

X¹⁰⁰⁰ + Y¹⁰⁰⁰ = 6,912

X²⁰⁰⁰ + Y²⁰⁰⁰ = 33,76244

X³⁰⁰⁰ + Y³⁰⁰⁰ = ?

Answer 1

Đặt \(a=x^{1000},b=y^{1000}\)
\(\Rightarrow a+b=6,912\) và \(a^2+b^2=33,76244.\)
Ta có \(\text{a+b= 6,912}\)
\(\Rightarrow\) \(\left(a+b\right)^2=6,912^2\)
\(\Leftrightarrow \)\(a^2+2ab+b^2=47,775744\)
\(\Leftrightarrow ab=\frac{47,775744-30,76244}{2}\)
\(\Leftrightarrow ab=8,506052\)
\(\Leftrightarrow ab(a+b)=58,797978624\)
Ta lại có \(a^3+b^3+ab(a+b)=(a+b)(a^2+b^2)\)
\(\Leftrightarrow \)\(a^3+b^3=174,5680067\)
Vậy \(x^{3000}+y^{3000}=174,5680067\)