a) Ta có :
\(x^{10}=1^x\)
Mà \(1^x=1\)
\(\Leftrightarrow x^{10}=1\)
\(\Leftrightarrow x^{10}=1^{10}\)
\(\Leftrightarrow x=1\left(tm\right)\)
Vậy .............
b) \(2^x-15=17\)
\(\Leftrightarrow2^x=17+15\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\left(tm\right)\)
Vậy ...................
x10 = 1x
<=> x10 = 1
<=> x10 = 110
<=> x = 1
2x - 15 = 17
<=> 2x = 32
<=> 2x = 25
<=> x = 5
@nguyen thi mai linh
x^10=1^x
x^10=1
x^10=1^10
Suy ra x=1
2^x - 15 = 17
2^x=17+15
2^x=32
2^x=2^5
Suy ra x=5