\(\dfrac{x}{-15}=\dfrac{-60}{x}=>x^2=-60.-15=900=>x=30\)
\(\dfrac{x}{-15}=\dfrac{-60}{x}\)
⇔\(x.x=-15.-60\)
⇔\(x^2=900\)
⇔\(\left[{}\begin{matrix}x=\sqrt{900}\\x=-\sqrt{900}\end{matrix}\right.\)
⇔\(\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\)
\(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow x^2=900\)
hay \(x\in\left\{30;-30\right\}\)