`(x-7,025)xx2,5=27,75`
`x-7,025 = 27,75 : 2,5`
`x-7,025 =11,1`
`x=11,1 + 7,025`
`x=18,125`
Vậy `x=18,125`
`#LeMichael`
\(( x − 7 , 025 ) × 2 , 5 = 27 , 75\)
\(x − 7 , 025 = 27 , 25 : 2 , 5\)
\(x − 7 , 025 = 11 , 1 \)
\(x = 11 , 1 + 7 , 025 \)
\(x = 18 , 125 \)
vậy \(x = 18 , 125 \)