Question

_{^{​​\(x-6\sqrt{x}+9=0\)}}

Answer 1

\(x-6\sqrt{x}+9=0\)

\(\Leftrightarrow\left(\sqrt{x}\right)^2-2\sqrt{x}.3+3^2=0\)

\(\Leftrightarrow\left(\sqrt{x}-3\right)^2=0\)

\(\Leftrightarrow\sqrt{x}=3\)

\(\Leftrightarrow x=9\)

Answer 2

đkxđ bn tự tìm nha^_^

\(x-6\sqrt{x}+9=0\Leftrightarrow\left(\sqrt{x}-3\right)^2=0\Leftrightarrow\sqrt{x}=3\Leftrightarrow x=9\)

vậy.......................