(1) (x-5)=0 => x=5
(2) (x2-9)=0 => x2=9
x=\(\sqrt{9}\)=3
vậy x=5 và x=9
\(\left(x-5\right)\left(x^2-9\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-5=0\rightarrow x=5\\x^2-9=0\rightarrow x^2=9\rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=5\\x=3\\x=-3\end{matrix}\right.\)