<=>\(\left(x-3\right)\sqrt{2x^2+2}=x^2-2x-3=\left(x-3\right)\left(x+1\right)\)
<=>x-3 =0 =>x =3
x khác 3
\(\Leftrightarrow\sqrt{\left(2x^2+2\right)}=x+1\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-1\\2x^2+2=\left(x^2+2x+1\right)\end{matrix}\right.\) <=>x^2 -2x+1 =0 => x =1
x={1;3}
Giải pt, bất pt
a) \(\left(\sqrt{x+3}-\sqrt{x+1}\right)\left(x^2+\sqrt{x^2+4x+3}=2x\right)\)
b) \(\left(x^2-3x+2\right)\left(x^2-12x+32\right)\le4x^2\)
c) \(2\sqrt{3x+7}-5\sqrt[3]{x-6}=4\)
Giải các bất pt sau:
a. \(\left|\frac{3-2x}{x+2}\right|\le\) 2x+3
b. (x+3)(x+2)-\(4\sqrt{x^2+4x+1}\)< 1
Giải pt
a) \(\sqrt[3]{81x-8}=x^3-2x^2+\dfrac{4}{3}x-2\)
b) \(\left(x+1\right)\left(\sqrt{x^2+2}+\sqrt{x^2+2x+3}\right)>\sqrt{x^2+2}-2x-1\)
giải pt: \(\sqrt[3]{x+5}+\sqrt[3]{x+6}=\sqrt[3]{2x+11}\)
Giải bất phương trình: \(\sqrt{x+1}\le\frac{x^2-x-2\sqrt[3]{2x+1}}{\sqrt[3]{2x+1}-3}\)
giúp mình giải bpt vs
\(\dfrac{\left|2x-1\right|-x}{2x}>1;\dfrac{2-\left|x-2\right|}{x^2-1}\ge0;\dfrac{\sqrt{x+4}-2}{4-9x^2}\le0;\dfrac{x^2-2x-3}{\sqrt[3]{3x-1}+\sqrt[3]{4-5x}}\ge0;\)\(3x^2-10x+3\ge0;\left(\sqrt{2}-x\right)\left(x^2-2\right)\left(2x-4\right)< 0;\dfrac{1}{x+9}-\dfrac{1}{x}>\dfrac{1}{2};\dfrac{2}{1-2x}\le\dfrac{3}{x+1}\)
giải bất phương trình:
\(\sqrt{x+1}\le\dfrac{x^2-x-2\sqrt[3]{2x+1}}{\sqrt[3]{2x+1}-3}\)
giải các bất phương trình sau:\(\frac{2x-5}{\left|x-3\right|}+1>0\)
\(\frac{\left|x-2\right|}{x^2-5x+6}>=3\)
\(\sqrt{2x+\sqrt{6x^2+1}}>x+1\)
\(\sqrt{x+3}-\sqrt{7-x}>\sqrt{2x-8}\)
\(\sqrt{2-x}>\sqrt{7-x}-\sqrt{-3-2x}\)
\(\sqrt{2x+3}+\sqrt{x+2}\le1\)
\(\left(x+5\right)\left(x-2\right)+3\sqrt{x\left(x+3\right)}>0\)
giải BPT : \(\sqrt{x+3}-\sqrt{7-x}+x^3-2x^2-2x-4\ge0\)
