\(\left(\dfrac{x-2016}{2017}\right)^2+\left(\dfrac{y+2016}{2017}\right)^2=0\)
Với mọi \(x\in R\) ta có: \(\left(\dfrac{x-2016}{2017}\right)^2+\left(\dfrac{y+2016}{2017}\right)^2\ge0\)
Dấu "=" xảy ra khi: \(\left\{{}\begin{matrix}x=2016\\y=-2016\end{matrix}\right.\)