Question

x-2 căn bậc x=0

Answer 1

 

 

Answer 2

ĐKXĐ: \(x\ge0\)

Ta có: \(x-2\sqrt{x}=0\)

\(\Leftrightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\\sqrt{x}-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\\sqrt{x}=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(nhận\right)\\x=4\left(nhận\right)\end{matrix}\right.\)

Vậy: S={0;4}

Answer 3

\(\left(x-2\right)^x=0\)

=> x-2 = 0

=> x = 2