\(\dfrac{1}{x-1}-\dfrac{1}{x+1}< 0\Leftrightarrow\dfrac{x+1-\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}< 0\)
\(\Leftrightarrow\dfrac{2}{\left(x-1\right)\left(x+1\right)}< 0\Leftrightarrow\left(x-1\right)\left(x+1\right)< 0\)
\(\Rightarrow-1< x< 1\) hay \(x\in\left(-1;1\right)\)
Đáp án D