\(\widehat{nOt}=\widehat{mOn}-\widehat{mOt}=110^o-20^o=90^o\)
có
\(\widehat{mOt}+\widehat{nOt}=\widehat{mOn}\)
\(=>20^o+\widehat{nOt}=110^o\\ =>\widehat{nOt}=110^o-20^o=90^o\)
Ta có:
\(\widehat{nOt}=\widehat{mOn}-\widehat{mOt}=110^o-20^o=90^o\)
Vậy: \(\widehat{nOt}=90^o\)