Question

TÍNH:

a)\(10.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)

 

b)\(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)

Answer 1

a) 100.75

b)\(\frac{-7}{6}\)

Answer 2

n=ghi lộn nhé !!

a)\(10.\sqrt{0,01.\sqrt{ }\frac{16}{9}}+3\sqrt{49-\frac{1}{6}}\sqrt{4}\)

Answer 3

a, \(10.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)

= 10 . 10 - \(\frac{1}{4}\) + 1

= 100 - \(\frac{1}{4}+1\)

= 99,75 + 1 = 100,75

b, \(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)

= \(\left(\frac{1}{9}\right)^{25}.\left(-9\right)^{25}-\frac{1}{6}\)

= \(\left(\frac{1}{9}.-9\right)^{25}-\frac{1}{6}\)

\(\left(-1\right)^{25}-\frac{1}{6}\)

= \(-1-\frac{1}{6}=\frac{-7}{6}\)

Answer 4

a)\(10.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)

\(=10.\sqrt{10^2}-\sqrt{\left(\frac{1}{4}\right)^2}+1\)

\(=10.10-\frac{1}{4}+1\)

\(=100-0,25+1\)

\(=100,75\)

^_^