Question

Tính:

a) \(\left( {x + 1} \right)\left( {{x^2} - x + 1} \right)\)                                              b) \(\left( {2x - \dfrac{1}{2}} \right)\left( {4{x^2} + x + \dfrac{1}{4}} \right)\)

Answer 1

a) \(\left(x+1\right)\left(x^2-x+1\right)\)

\(=x^3+1\)

b) \(\left(2x-\dfrac{1}{2}\right)\left(4x^2+x+\dfrac{1}{4}\right)\)

\(=8x^3-\dfrac{1}{8}\)

Answer 2

`a, (x+1)(x^2-x+1) = x^3 - 1`

`b, (2x-1/2)(4x^2 + x + 1/4) = 8x^3 - 1/8`