\(27\dfrac{51}{59}-\left(7\dfrac{51}{59}-\dfrac{1}{3}\right)=\dfrac{1614}{59}-\left(\dfrac{464}{59}-\dfrac{1}{3}\right)=\dfrac{1614}{59}-\dfrac{1333}{177}=\dfrac{3509}{177}\)
\(27\dfrac{51}{59}-\left(7\dfrac{51}{59}-\dfrac{1}{3}\right)=27\dfrac{51}{59}-7\dfrac{51}{59}+\dfrac{1}{3}=27+\dfrac{51}{59}-7-\dfrac{51}{59}+\dfrac{1}{3}=20+\dfrac{1}{3}=\dfrac{61}{3}\)