a.
\(\left(xy\right).\left(yz\right).\left(xz\right)=3.6.18\\ \Rightarrow\left(x.y.z\right)^2=324\\ \Rightarrow\left[{}\begin{matrix}x.y.z=18\\x.y.z=-18\end{matrix}\right.\)
Nếu x.y.z=18
\(\Rightarrow\left[{}\begin{matrix}z=\left(xyz\right):\left(xy\right)=18:3=6\\x=\left(xyz\right):\left(yz\right)=18:6=3\\y=\left(xyz\right):\left(xz\right)=18:18=1\end{matrix}\right.\)
Nếu x.y.z = -18
\(\Rightarrow\left\{{}\begin{matrix}z=-6\\x=-3\\y=-1\end{matrix}\right.\)
Vậy...
a)Ta có:xy.yz.xz=3.6.18
x^2.y^2.z^2=324
(x.y.z)^2=18^2
x.y.z=18
Do đó:x=18:6=3
y=18:18=1
z=18:3=6
b)Ta có:xy.yz.xz=1.8.18
x^2.y^2.z62=144
(x.y.z)^2=12^2
x.y.z=12
Do đó:x=12:8=1,5
y=12:18=2/3
z=12:1=12
