Question

tính tổng : A= \(2010/2+2011/6+2010/12+......+2010/9900\)

Answer 1

\(A=\dfrac{2010}{2}+\dfrac{2010}{6}+...+\dfrac{2010}{9900}\\ =2010\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{9900}\right)\\ =2010\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right)\\ =2010\left(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)\\ =2010.\dfrac{99}{100}=\dfrac{19899}{10}\)