a, \(n_{O_2}=\dfrac{1,5.10^{23}}{6.10^{23}}=0,25\left(mol\right)\)
\(V_{O_2}=0,25.22,4=5,6\left(l\right)\)
b,\(n_{SO_2}=\dfrac{32}{64}=0,5\left(mol\right)\)
\(V_{SO_2}=0,5.22,4=11,2\left(l\right)\)
\(V_{O_2\left(đktc\right)}=n.22,4=1,5.22,4=33,6\left(l\right)\)
\(V_{SO_2\left(đktc\right)}=n.22,4=\dfrac{m}{M}.22,4=\dfrac{32}{64}.22,4=11,2\left(l\right)\)