Bài 1: Căn bậc hai
Các câu hỏi tương tự
rút gọn các biểu thức sau:
a,\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b,\(\sqrt{6+2\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
c,\(\sqrt{2+\sqrt{5-\sqrt{13-\sqrt{48}}}}\)
d,\(\left(3-\sqrt{5}\right)\sqrt{3+\sqrt{5}}+\left(3+\sqrt{5}\right)\sqrt{3-\sqrt{5}}\)
1,\(\sqrt{49-12\sqrt{ }5}+\sqrt{49+12\sqrt{ }5}\)
2,\(\sqrt{29+12\sqrt{ }5}\)+\(\sqrt{29-12\sqrt{ }5}\)
3,\(\sqrt{31-12\sqrt{ }3}-\sqrt{31+12\sqrt{ }3}\)
4,\(\sqrt{39-12\sqrt{ }3}-\sqrt{39+12\sqrt{ }3}\)
Câu a :
\(\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
Câu b:
\(\sqrt{\sqrt{5-\sqrt{3-\sqrt{29-12\sqrt{5}}}}}\)
Tính B=\(\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\)
C=\(\sqrt{94-42\sqrt{5}}-\sqrt{94+42\sqrt{5}}\)
D=\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
E=\(\sqrt{6+\sqrt{24}+\sqrt{12}+\sqrt{8}}-\sqrt{3}-\sqrt{2}-15\)
F=\(\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)
Thực hiện phép tính:
a) \(\sqrt{24+8\sqrt{5}}-\sqrt{9-4\sqrt{5}}.\)
b) \(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\).
c) \(\dfrac{1}{1+\sqrt{2}}+\dfrac{1}{\sqrt{2}+\sqrt{3}}+\dfrac{1}{\sqrt{3}+\sqrt{4}}+....+\dfrac{1}{\sqrt{99}+\sqrt{100}}.\)
Bài 1: Tính
a sqrt{6+2sqrt{5}} + sqrt{6-2sqrt{5}}
b sqrt{5+2sqrt{6}} + sqrt{5-2sqrt{6}}
c sqrt{8-2sqrt{7}} - sqrt{8+2sqrt{7}}
d sqrt{29+12sqrt{5}} + sqrt{29-12sqrt{5}}
e ( sqrt{0,25} - sqrt{225} + sqrt{2,25}) : sqrt{169}
f 3 - sqrt{5} + 3 + sqrt{5}
Đọc tiếp
Bài 1: Tính
a> \(\sqrt{6+2\sqrt{5}}\) + \(\sqrt{6-2\sqrt{5}}\)
b> \(\sqrt{5+2\sqrt{6}}\) + \(\sqrt{5-2\sqrt{6}}\)
c> \(\sqrt{8-2\sqrt{7}}\) - \(\sqrt{8+2\sqrt{7}}\)
d> \(\sqrt{29+12\sqrt{5}}\) + \(\sqrt{29-12\sqrt{5}}\)
e> ( \(\sqrt{0,25}\) - \(\sqrt{225}\) + \(\sqrt{2,25}\)) : \(\sqrt{169}\)
f> 3 - \(\sqrt{5}\) + 3 + \(\sqrt{5}\)
Rút gọn
a)
A= \(\sqrt {a - 2 - 2\sqrt {a-3}} - \sqrt {a+1-4\sqrt {a-3}} (3<=a<=4)\)\(B= \sqrt {\sqrt 5 -\sqrt{3 - \sqrt{29 - 12\sqrt 5}}} × \sqrt{2003-2\sqrt{2005-2\sqrt2004}}\)
Rút gọn biểu thức
a. \(A=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-\sqrt{12\sqrt{5}}}}}\)
b. \(B=\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\left(\sqrt{4-\sqrt{15}}\right)\)
Mn giúp mình vs.. mình đang cần gấp ạ, cảm ơn mn nhiều lắm.. hjx
sqrt{46-6sqrt{ }5}-sqrt{29-12sqrt{ }5}
sqrt{7-3sqrt{ }5}
left(3-sqrt{ }2right)sqrt{11+6sqrt{ }2}
sqrt{4+sqrt{ }15}
left(sqrt{ }5+sqrt{ }7right)sqrt{12-2sqrt{ }35}
sqrt{17-12sqrt[]{}2}
sqrt{14-6sqrt{ }5}
sqrt{27-12sqrt{ }5}
Đọc tiếp
\(\)Mn giúp mình vs.. mình đang cần gấp ạ, cảm ơn mn nhiều lắm.. hjx
\(\sqrt{46-6\sqrt{ }5}-\sqrt{29-12\sqrt{ }5}\)
\(\sqrt{7-3\sqrt{ }5}\)
\(\left(3-\sqrt{ }2\right)\sqrt{11+6\sqrt{ }2}\)
\(\sqrt{4+\sqrt{ }15}\)
\(\left(\sqrt{ }5+\sqrt{ }7\right)\sqrt{12-2\sqrt{ }35}\)
\(\sqrt{17-12\sqrt[]{}2}\)
\(\sqrt{14-6\sqrt{ }5}\)
\(\sqrt{27-12\sqrt{ }5}\)