Bài trên mình làm sai nha
\(2KClO_3\rightarrow2KCl+3O_2\)
\(n_{O_2}=\dfrac{V}{22,4}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\)
Theo PTHH, \(n_{KClO_3}=\dfrac{2}{3}n_{O_2}=\dfrac{2}{3}\cdot1,5=1\left(mol\right)\)
\(m_{KClO_3}=n\cdot M=1\cdot122,5=122,5\left(g\right)\)
Ngọc HiềnHà Vi
nO2=33,6/22,4=1,5mol
PTHH: 2KClO3->2KCl+3O2
TheoPT:2mol 3mol
Theo bài:1mol 1,5mol
mKClO3=1.122,5=122,5g
\(2KClO_3\rightarrow2KCl+3O_2\)
\(n_{O_2}=\dfrac{m}{M}=\dfrac{33,6}{32}=1,05\left(mol\right)\)
Theo PTHH, \(n_{KClO_3}=\dfrac{2}{3}n_{O_2}=\dfrac{2}{3}\cdot1,05=0,7\left(mol\right)\)
\(m_{KClO_3}=n\cdot M=0,7\cdot122,5=85,75\left(g\right)\)
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