\(M_{CuO}=80\)
Trong 1 mol hc có 1 mol Cu, 1 mol O.
\(\%Cu=\dfrac{64}{80}.100\%=80\%\)
\(M_{CuO}=64+16=80\left(g\right)\)
\(\Rightarrow\%Cu=\dfrac{64}{80}\times100\%=80\%\)
\(\%O=100\%-80\%=20\%\)
\(M_{CuO}=64+16=80\left(g/mol\right)\)
\(\%Cu=\dfrac{64}{80}.100\%=80\%\)
\(\%O=100\%-80\%=20\%\)