Question

Tính giá trị biểu thức:

D = (-2)\(^3\)\(.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\) E = 5\(\sqrt{16}-4\sqrt{9}+\sqrt{25}-0,3\sqrt{400}\)

F = \(\left(-\frac{3}{2}\right)^2+\left|-\frac{5}{6}\right|-1\frac{1}{2}:6\)

 

 

Answer 1

d: \(D=-8\cdot\left(\dfrac{3}{4}-\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)

\(=-8\cdot\dfrac{1}{2}:\dfrac{27-14}{12}\)

\(=-4:\dfrac{13}{12}\)

\(=-4\cdot\dfrac{12}{13}=-\dfrac{48}{13}\)

e: \(E=5\cdot4-4\cdot3+5-0.3\cdot20\)

=20-12+5-6

=8+5-6

=13-6=7

f: \(F=\dfrac{9}{4}+\dfrac{5}{6}-\dfrac{3}{2}:6\)

\(=\dfrac{9}{4}+\dfrac{5}{6}-\dfrac{3}{12}\)

\(=\dfrac{27}{12}+\dfrac{10}{12}-\dfrac{3}{12}=\dfrac{34}{12}=\dfrac{17}{6}\)