Question

Tính:

F= \(\left(\frac{\sqrt{x}}{\sqrt{x}+2}-\frac{x+2}{x-4}\right):\left(\frac{2\sqrt{x}-1}{x-2\sqrt{x}}-\frac{1}{\sqrt{x}}\right)\)

Answer 1

123

Answer 2

dễ mừ

Answer 3

F = \(\left(\frac{\sqrt{x}}{\sqrt{x}+2}-\frac{x+2}{x-4}\right):\left(\frac{2\sqrt{x}-1}{x-2\sqrt{x}}-\frac{1}{\sqrt{x}}\right)\)

= \(\frac{\sqrt{x}\left(\sqrt{x}-2\right)-x-2}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}:\frac{2\sqrt{x}-1-\sqrt{x}+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\)

= \(\frac{-2\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}.\frac{\left(\sqrt{x}-2\right)\sqrt{x}}{\sqrt{x}+1}\)

= \(\frac{-2\sqrt{x}}{\sqrt{x}+2}\)