Question

Tính

a,\(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right).\left(-3\dfrac{1}{6}+3\dfrac{1}{7}\right)+7.5\)

Answer 1

\(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right).\left(-3\dfrac{1}{6}+3\dfrac{1}{7}\right)+7.5\)

=\(\left(\dfrac{7}{3}+\dfrac{7}{2}\right).\left(-\dfrac{19}{6}+\dfrac{22}{7}\right)+35\)

=\(\dfrac{35}{6}.\dfrac{-1}{42}+35=-\dfrac{5}{36}+35\)

=\(\dfrac{1255}{36}\)

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Answer 2

\(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right).\left(-3\dfrac{1}{6}+3\dfrac{1}{7}\right)+7.5\)

\(=\left(\dfrac{7}{3}+\dfrac{7}{2}\right).\left(-\dfrac{19}{6}+\dfrac{22}{7}\right)+35\)

\(=\dfrac{35}{6}.\dfrac{-1}{42}+35=-\dfrac{5}{36}+35\)

\(=\dfrac{1255}{36}\)

Chúc bạn học tốt!!!