Question

Tính:

a) \(\sqrt{3-2\sqrt{2}}-\sqrt{3+2\sqrt{2}}\)

b)\(\sqrt{4-2\sqrt{3}}-\sqrt{4+2\sqrt{3}}\)

Answer 1

a)\(\sqrt{3-2\sqrt{2}}-\sqrt{3+2\sqrt{2}}\)

=\(\sqrt{\left(\sqrt{2}\right)^2-2.\sqrt{2}.1+1}-\sqrt{\left(\sqrt{2}\right)^2+2.\sqrt{2}.1+1}\)=\(\sqrt{\left(\sqrt{2}-1\right)^2}-\sqrt{\left(\sqrt{2}+1\right)^2}\)

=\(\left(\sqrt{2}-1\right)-\left(\sqrt{2}+1\right)\)

=\(\sqrt{2}-1-\sqrt{2}-1=-2\)

Câu b) tương tự bạn nhe

Answer 2

a) \(=\sqrt{\left(\sqrt{2}-1\right)^2}-\sqrt{\left(\sqrt{2}+1\right)^2}\)

\(=\sqrt{2}-1-\left(\sqrt{2}+1\right)=-2\)

b) \(=\sqrt{\left(\sqrt{3}-1\right)^2}-\sqrt{\left(\sqrt{3}+1\right)^2}\)

\(=\sqrt{3}-1-\left(\sqrt{3}+1\right)=-2\)