A = \(\frac{2}{3}+\frac{5}{6}:6-\frac{1}{8}.\left(-3\right)^2\)
A = \(\frac{2}{3}+\frac{5}{6}.\frac{1}{6}-\frac{1}{8}.9\)
A = \(\frac{2}{3}+\frac{5}{36}-\frac{9}{8}\)
A =\(\frac{-23}{72}\)
A = \(\frac{2}{3}+\frac{5}{6}:6-\frac{1}{8}.\left(-3\right)^2\)
A = \(\frac{2}{3}+\frac{5}{6}.\frac{1}{6}-\frac{1}{8}.9\)
A = \(\frac{2}{3}+\frac{5}{36}-\frac{9}{8}\)
A =\(\frac{-23}{72}\)
rút gọn biểu thức:
C=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
Tính
a. \(\frac{\left(13\frac{1}{4}-2\frac{5}{7}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
1, So sánh A và B biết A=\(\dfrac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\) B=\(\dfrac{4}{35}+\dfrac{4}{63}+\dfrac{4}{99}+\dfrac{4}{143}+\dfrac{4}{195}\) ( GIÚP Mk Với Mk Đang Cần Gấp )
Tính \(E=\left[\frac{1\frac{11}{31}.4\frac{3}{7}-\left(15-6\frac{1}{3}.\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}.\left(-1\frac{14}{93}\right)\right].\frac{31}{50}\)
A = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\) _\(\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
tính\(\left[\frac{\left(4,6+5.6,25\right).14}{4.0,125+2,3}:\frac{17}{6}\right]:\frac{27.9\frac{3}{5}}{12,4+4\frac{2}{5}}+\left(4\frac{5}{8}-\frac{13}{6}:8\frac{2}{3}\right):\left(3,25:2\frac{1}{4}\right)\)
giải hộ milk bài này nha
\(\frac{\left(13\frac{1}{4}-2\frac{5}{7}-10\frac{5}{6}\right)\times230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
giải hộ milk nha cảm ơn rất nhiều
Rút gọn
C = \(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
D = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
E = \(\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Bài 1
a) thực hiện phép tính A=\(\frac{2^{12}\times3^5-4^6\times9^2}{\left(2^2\times3\right)^6+8^4\times3^5}-\frac{5^{10}\times7^3+25^5\times49^2}{\left(125\times7\right)^3+5^9\times14^3}\)
b) CMR: Với mọi số nguyên dương n thì:\(3^{n+2}-2^{n+2}+3^n-2^n\) chia hết cho 10