Question

Tính : A = [900−(2)²]. [900−(−6)²] . [900−(−8)²].....[900−(−88)²].[900−(−900)²]

Mong là ai làm được sẽ giúp mình. Mọi người hãy giúp mình nhé!

Answer 1

\(\left(900-2^2\right).\left(900-\left(-6\right)^2\right).\left(900-\left(-8\right)^2\right)...\left(900-\left(-88\right)^2\right)\left(900-\left(-900^2\right)\right)\\ =\left(900-2^2\right).\left(900-\left(-6\right)^2\right).....\left(900-\left(-30\right)^2\right)....\left(900-\left(-88\right)^2\right)\left(900-\left(-900\right)^2\right)\\ =\left(900-2^2\right)\left(900-\left(-6\right)^2\right)....\left(900-900\right)...\left(900-\left(-900\right)^2\right)\\ =\left(900-2^2\right)....0...\left(900-\left(-900\right)^2\right)\\ =0\)

Answer 2

Đề gì mà ko có quy luật v

Answer 3

tính tổng à......mik sẽ giúp được đấy

Answer 4

(900−22).(900−(−6)2).(900−(−8)2)...(900−(−88)2)(900−(−9002))=(900−22).(900−(−6)2).....(900−(−30)2)....(900−(−88)2)(900−(−900)2)=(900−22)(900−(−6)2)....(900−900)...(900−(−900)2)=(900−22)....0...(900−(−900)2)=0