Question

Tính

a, \(5\dfrac{4}{13}.14\dfrac{3}{41}-5\dfrac{4}{13}.2\dfrac{3}{41}\)

b, \(\dfrac{2^3}{3^3}:\dfrac{16}{27}+\dfrac{2017}{2018}-\dfrac{1}{2}.2017^0\)

c, \(3:\left(\dfrac{-3}{2}\right)^2+\dfrac{1}{9}.\sqrt{36}\)

Answer 1

a, \(5\dfrac{4}{13}.15\dfrac{3}{41}-5\dfrac{4}{13}.2\dfrac{3}{41}\)

\(=\left(15\dfrac{3}{41}-2\dfrac{3}{41}\right).\dfrac{69}{13}=\dfrac{13.69}{13}=69\)

b, \(\dfrac{2^3}{3^3}:\dfrac{16}{27}+\dfrac{2017}{2018}-\dfrac{1}{2}.2017^0\)

\(=\dfrac{8}{27}:\dfrac{16}{27}+\dfrac{2017}{2018}-\dfrac{1}{2}.1=\dfrac{1}{2}+\dfrac{2017}{2018}-\dfrac{1}{2}=\dfrac{2017}{2018}\)

c, \(3:\left(-\dfrac{3}{2}\right)^2+\dfrac{1}{9}.\sqrt{36}=3:\dfrac{9}{4}+\dfrac{1}{9}.6=\dfrac{4}{3}+\dfrac{2}{3}=\dfrac{6}{3}=2\)

Answer 2

a,

\(5\dfrac{4}{13}.14\dfrac{3}{41}-5\dfrac{4}{13}.2\dfrac{3}{41}=5\dfrac{4}{13}.\left(14\dfrac{3}{41}-2\dfrac{3}{41}\right)\)

=\(5\dfrac{4}{13}.13\)

=\(\dfrac{69}{13}.13\)

=69