Question

Tính

a,(-0,1)².(-0.1)³

b,125²:25³

c,(7³)²:(7²)³

d,\(\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{^{ }\left(2.3\right)^6.\left(2^5\right)^3}\)

Answer 1

a,(-0,1)².(-0,1)³=0,01.(-0,001)

=-0,00001

b,125²:25³=(5³)²:(5²)³

=5⁶:5⁶=1

c,\(\left(7^3\right)^2:\left(7^2\right)^3=7^6:7^6=1\)

d,\(\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{\left(2.3\right)^6.\left(2^5\right)^3}=\dfrac{3^6.2^{15}}{2^6.3^6.2^{15}}=\dfrac{3^6.2^{15}}{3^6.2^{21}}\)

\(\dfrac{1}{2^6}=\dfrac{1}{64}\)

Answer 2

a)\(\left(-0,1\right)^2.\left(-0,1\right)^3=\left(-0,1\right)^5\)

b) \(125^2:25^3=\left(5^3\right)^2:\left(5^2\right)^3=5^6:5^6=1\)

c) \(\left(7^3\right)^2:\left(7^2\right)^3=7^6:7^6=1\)

d) \(\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{\left(2.3\right)^6.\left(2^5\right)^3}=\dfrac{3^6.2^{15}}{2^6.3^6.2^{15}}=\dfrac{1}{2^6}=\dfrac{1}{64}\)

Answer 3

\(a,\left(-0,1\right)^2.\left(-0,1\right)^3=0,01.\left(-0,001\right)=-0,0001\\ b,125^2:25^3=\left(5^3\right)^2:\left(5^2\right)^3=5^6:5^6=1\\ c,\left(7^3\right)^2:\left(7^2\right)^3=7^6:7^6=1\\ d,\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{\left(2.3\right)^6.\left(2^5\right)^3} =\dfrac{3^6.2^{15}}{2^6.3^6.2^{15}}=\dfrac{1}{2^6}=\dfrac{1}{64}\)

Answer 4

a) \(\left(-0,1\right)^2.\left(-0,1\right)^3=\left(-0,1\right)^{2+3}=\left(-0,1\right)^5\)

b) \(125^2:25^3=\left(5^3\right)^2:\left(5^2\right)^3=5^6:5^6=5^{6-6}=5^0=1\)

c)\(\left(7^3\right)^2:\left(7^2\right)^3=7^6:7^6=7^{6-6}=7^0=1\)

d)\(\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{\left(2.3\right)^6.\left(2^5\right)^3}=\dfrac{3^6.2^{15}}{2^6.3^6.2^{15}}=\dfrac{1}{2^6}=\dfrac{1}{64}\)