\(<=>15\sqrt{x+3} - 3\sqrt{x+3}=4\sqrt{x+3} <=> 15\sqrt{x+3} - 3\sqrt{x+3}-4\sqrt{x+3}=0 <=> 8\sqrt{x+3}=0 <=>\sqrt{x+3}=0 => x+3=0 =>x=-3\)
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Ôn tập chương 1: Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
TÍNH: \(15\sqrt{x+1}-\sqrt{9x+9}=3\sqrt{4x+4}+12\)
Giải phương trình
\(a.\dfrac{3}{4}\sqrt{4x}-\sqrt{4x}+5=\dfrac{1}{4}\sqrt{4x}\)
\(b.\sqrt{3-x}-\sqrt{27-9x}+1,25.\sqrt{48-16x}=6\)
\(c.\dfrac{5\sqrt{x}-2}{8\sqrt{x}+2,5}=\dfrac{2}{7}\)
\(d.\sqrt{9x^2+12x+4}=4\)
Giải PT:
a) -5x+7\(\sqrt{x}\) +12=0
b) \(\dfrac{1}{3}\)\(\sqrt{4x^2-20}\) +2\(\sqrt{\dfrac{x^2-5}{9}}\) -3\(\sqrt{x^2-5}=0\)
c) \(\sqrt{9x+27}+5\sqrt{x+3}-\dfrac{3}{4}\sqrt{16x+48}=5\)
d) \(\sqrt{49x-98}-14\sqrt{\dfrac{x-2}{49}}=3\sqrt{x-2}+8\)
\(\sqrt{9x-27}+\sqrt{x-3}-\frac{1}{2}\sqrt{4x-12}\)
\(\left(\frac{\sqrt{x}}{2}-\frac{1}{2\sqrt{x}}\right)\left(\frac{x-\sqrt{x}}{\sqrt{x}+1}-\frac{x+\sqrt{x}}{\sqrt{x}-1}\right)\)
1) Giải phương trình: a) \(5\sqrt{\dfrac{9x-27}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{91}}=0\) b) \(\sqrt{x}+\sqrt{y-1}+\sqrt{z-2}=\dfrac{1}{2}\left(x+y+z\right)\)
Gỉai phương trình
a) \(\frac{3}{4}\sqrt{5x}-\sqrt{4x}+5=\frac{1}{4}\sqrt{4x}\)
b) \(\sqrt{3-x}-\sqrt{27-9x}+1,25\sqrt{48-16x}=6\)
c) \(\frac{5\sqrt{x}-2}{8\sqrt{x}+2,5}=\frac{2}{7}\)
d) \(\sqrt{3x^2+12x+4}=4\)
\(\sqrt{9x-18}+5\sqrt{4x-8}=\sqrt{x-2}+3\)
giải phương trình
a, \(\sqrt{4x-20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
b, \(2x-x^2+\sqrt{6x^2-12x+7}=0\)
c, \(\dfrac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}\)
a,\(\sqrt{x^2-6x+9}=3\) b,\(\sqrt{4x+20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x+45}=4\)