\(3^{3n+1}=9^{n+2}\)
\(\Rightarrow3^{3n+1}=3^{2\left(n+2\right)}\)
\(\Rightarrow3n+1=2n+4\)
\(\Rightarrow3n-2n=4-1\)
\(\Rightarrow n=3\)
Vậy n=3 thì \(3^{3n+1}=9^{n+2}\)
Tim x∈Z thoa man 33n+1=9n+2
Cho f(x)=5x. Tim x thoa man f(x2-1) - f(x)=100
tim gia tri cua bieu thuc X=2x^5-5y^3+2015 tai x,y thoa man /x-1/=(y+2)^20=0
tim cac cap so nguyen ( x ; y ) thoa man : xy - x - y = 2
Tim x,y,z nguyen duong t/man 1/x +1/y +1/z=2
Cho 3 so x, y, z thoa man xyz = 2018. CMR :
\(\dfrac{2018x}{xy+2018+2018z}+\dfrac{y}{yz+y+2018}+\dfrac{z}{xz+z+1}=1\)
tim so tu nhien n<30 thoa man n,n+2,n+6 deu la snt
so bo (x;y;z) thoa man xy = \(\dfrac{2}{5}\); yz = \(\dfrac{3}{7}\);xz = -\(\dfrac{9}{13}\)
gia tri x thoa man 0.(12):(x-1)=1.(6):0.(4)
