Question

TÌm xϵZ để Pmax

P= 2019-(x+1)²⁰²⁰

Answer 1

\(\left(x+1\right)^{2020}\ge0\forall x\\ \Rightarrow-\left(x+1\right)^{2020}\le0\forall x\\ \Rightarrow2019-\left(x+1\right)^{2020}\le2019\forall x\\ \Rightarrow P\le2019\forall x\)

Dấu "=" xảy ra \(\Leftrightarrow\left(x+1\right)^{2020}=0\\ \Leftrightarrow x+1=0\\ \Leftrightarrow x=-1\)

Vậy GTLN của P = 2019

Answer 2

vì -(x+1)^2<0 => -(x+1)^2. (x+1)^2018<0 với mọi x => 2019-(x+1)^2020<2019

dấu "=" xảy ra khi x+1=0 <=> x= -1

vậy Pmax= 2019 khi x= -1