Ta có:
\(\dfrac{4x}{4.1}\)=\(\dfrac{3y}{2.3}\)=\(\dfrac{2z}{3.2}\)và 4x-3y+2z=36
Áp dụng t/c dãy tỉ số bằng nhau, ta có:
\(\dfrac{4x}{4}\)=\(\dfrac{3y}{6}\)=\(\dfrac{2z}{6}\)=\(\dfrac{4x-3y+2z}{4-6+6}\)=\(\dfrac{36}{4}\)=9
=>\(\dfrac{4x}{4}\)=9;=>4x=36
=>x=9
=>\(\dfrac{3y}{6}\)=9;=>3y=54
=>y=18
=>\(\dfrac{2z}{6}\)=9;=>2z=54
=>z=27
Vậy x=9, y=18, z=27