Ta có: \(4x-xy=15\)
\(\Rightarrow x\left(4-y\right)=15\)
\(\Rightarrow x\left(4-y\right)=15=3.5=5.3=1.15=15.1\) (Vì x,y thuộc N, 15 > 0)
Thay \(4-y=5\Rightarrow y=-1\)
\(4-y=3\Rightarrow y=1\)
\(4-y=15\Rightarrow y=-11\)
\(4-y=1\Rightarrow y=3\)
Vậy \(\left(x;y\right)\in\left\{\left(3;-1\right)\left(5;1\right)\left(1;-11\right)\left(15;3\right)\right\}\)