\(F=\frac{1}{9}\left(9x^2+9y^2+4-18xy-12x+12y\right)+\frac{4}{9}\left(9x^2-6x+1\right)+\frac{1}{9}\left(9y^2+6y+1\right)+2\)
\(F=\frac{1}{9}\left(3x-3y-2\right)^2+\frac{4}{9}\left(3x-1\right)^2+\frac{1}{9}\left(3y+1\right)^2+2\ge2\)
\(F_{min}=2\) khi \(\left\{{}\begin{matrix}x=\frac{1}{3}\\y=-\frac{1}{3}\end{matrix}\right.\)